5b^2-28b+32=0

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Solution for 5b^2-28b+32=0 equation:


Simplifying
5b2 + -28b + 32 = 0

Reorder the terms:
32 + -28b + 5b2 = 0

Solving
32 + -28b + 5b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(8 + -5b)(4 + -1b) = 0

Subproblem 1

Set the factor '(8 + -5b)' equal to zero and attempt to solve: Simplifying 8 + -5b = 0 Solving 8 + -5b = 0 Move all terms containing b to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -5b = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -5b = 0 + -8 -5b = 0 + -8 Combine like terms: 0 + -8 = -8 -5b = -8 Divide each side by '-5'. b = 1.6 Simplifying b = 1.6

Subproblem 2

Set the factor '(4 + -1b)' equal to zero and attempt to solve: Simplifying 4 + -1b = 0 Solving 4 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1b = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1b = 0 + -4 -1b = 0 + -4 Combine like terms: 0 + -4 = -4 -1b = -4 Divide each side by '-1'. b = 4 Simplifying b = 4

Solution

b = {1.6, 4}

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